University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 10 - Practice Exercises - Page 593: 27

Answer

$y=\dfrac{-3}{2}$

Work Step by Step

Here, we have $r=\dfrac{-3}{2}\csc \theta$ This implies that $r \sin \theta =\dfrac{-3}{2}$ Thus, we have $y=\dfrac{-3}{2}$
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