Answer
Domain of $f^{-1}$ = range of $f$ = $(0,1].$
Range of $f^{-1}$ = domain of $f$ = $[0,\infty)$
Work Step by Step
Follow the instructions:
1. Draw a line through $(0,0)$ and $(1,1)$: $y=x$.
2. Select a few points from the graph of f, and reflect them across $y=x.$
3. Join the new points with a smooth curve: graph of $f^{-1}(x)$
Domain of $f^{-1}$ = range of $f$ = $(0,1].$
Range of $f^{-1}$ = domain of $f$ = $[0,\infty)$
