Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 6: Applications of Definite Integrals - Section 6.4 - Areas of Surfaces of Revolution - Exercises 6.4 - Page 341: 27

Answer

$226.195 \space mm^3$

Work Step by Step

Our aim is to integrate the integral to compute the surface area. In order to solve the integral, we have: $Surface \space Area(S_A)= (2 \pi)\int_{a}^{b} y \sqrt {1+(\dfrac{dy}{dx})^2}$ or, $ =(2 \pi)\int_{7}^{16} \sqrt {256-x^2} \times \dfrac{256}{256-x^2} dx $ or, $ =[32 \pi x ]_{7}^{16}$ or, $ \approx 904.779$ The volume for each color is: $(904.779) \times (0.05 \space mm) = 45.2389 mm^3$ The required amount of liters of each color is $226.195 \space mm^3$
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