Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 6: Applications of Definite Integrals - Section 6.3 - Arc Length - Exercises 6.3 - Page 336: 18

Answer

$4.6984$

Work Step by Step

The formula to calculate the arc length is as follows: $L=\int_{c}^{d} \sqrt {1+[f'(x)]^2} dx$ Now, $f'(x)=x \sin x$ Re-write the equation as follows: $L=\int_{0}^{\pi} \sqrt {1+(x \space \sin x)^2} dx$ After calculations using a calculator: $l=4.6984$
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