Answer
$1$
Work Step by Step
Given: $\int_C (x-y) dx +(x+y) dy$
Now,
$\int_C (x-y) dx +(x+y) dy=\int_{0}^1 x dx+\int_{0}^1 (2x-2) dx+\int_{0}^1 y dy$
Thus, $(\dfrac{1}{2})+1-(\dfrac{1}{2})=1$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 16: Integrals and Vector Fields - Section 16.2 - Vector Fields and Line Integrals: Work, Circulation, and Flux - Exercises 16.2 - Page 955: 24
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