Answer
$-\frac{\pi}{3}\leq θ \leq \frac{\pi}{3} , secθ \leq r \leq 2$
Work Step by Step
$x^{y}+x^{y}=x^{y}$
$=> r=2$
$x=1 => r=secθ $
$secθ=2=>θ =\frac{\pi}{3}or -\frac{\pi}{3} $
$-\frac{\pi}{3}\leq θ \leq \frac{\pi}{3} , secθ \leq r \leq 2$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 15: Multiple Integrals - Section 15.4 - Double Integrals in Polar Form - Exercises 15.4 - Page 893: 6
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