Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 14: Partial Derivatives - Practice Exercises - Page 865: 49

Answer

$2y-z=2$

Work Step by Step

Formula to calculate the vector equation is:$\nabla f(r_0) \cdot (r-r_0)=0$ As we know that the equation of tangent for $\nabla f( 0,1,0)=\lt 0,2,-1 \gt$ is given by $0+2(y-1)-1(z-0)=0$ and $2y-2-z=0$ Thus, $2y-z=2$
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