Answer
$\approx 3464.1\ J$
Work Step by Step
The work done by a constant force ${\bf F}$ acting through a displacement ${\bf D}=\vec{PQ}$
is ${\bf W}={\bf F}\cdot{\bf D}$
---
${\bf F}\cdot{\bf D}=|{\bf F}|\cdot|{\bf D}|\cos\alpha$
${\bf W}=(200\ N)(20\ m)(\cos 30^{\circ})$
$=4000\displaystyle \cdot\frac{\sqrt{3}}{2}\ Nm$
$=2000\sqrt{3}\ J$
$\approx 3464.1\ J$