Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Appendices - Section A.3 - Lines, Circles, and Parabolas - Exercises A.3 - Page AP-17: 20

Answer

$(-2,-9)$

Work Step by Step

We find the second pair of coordinates: $ A(x_{1},y_{1})=\quad$... $ B(x_{2},y_{2})=(3,-3)\quad$ $\left\{\begin{array}{l} \Delta x=x_{2}-x_{1}=5\\ \Delta y=y_{2}-y_{1}=6 \end{array}\right.$ $\left\{\begin{array}{l} x_{1}=x_{2}-\Delta x=3-5=-2\\ \\ y_{1}=y_{2}-\Delta y=-3-6=-9 \end{array}\right.$ $A(x_{1},y_{1})=(-2,-9)$
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