Answer
$y=2$ or $y=-3$
Work Step by Step
$y^{2}+y-6$
=$y^{2} + 3y - 2y -6$
=$y(y+3)-2(y+3)$
=$(y-2)(y+3)$
$y=2$ or $y=-3$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 0 - Section 0.3 - Multiplying and Factoring Algebraic Expressions - Exercises - Page 21: 38
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