Answer
$\frac{4}{3}$
Work Step by Step
$3(\frac{1}{9}-(\frac{2}{3})^2)^2 +1$
$3(\frac{1}{9}-\frac{4}{9})^2 +1$
$3(\frac{-3}{9})^2 +1$
$3(\frac{9}{81}) +1$
$\frac{27}{81} +1$
$\frac{108}{81}$
$\frac{4}{3}$
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