Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 2 - Section 2.5 - Continuity - 2.5 Exercises - Page 125: 52

Answer

$f(3) \gt 6$

Work Step by Step

Let's assume that $f(3) \leq 6$ Since it is given in the question that $f(3) \neq 6$, then $f(3) \lt 6$ It is given that $f(2) = 8$ Note that $f(3) \lt 6 \lt f(2)$ Since $f$ is continuous on the interval $[1,5]$, there must be a number $c$ where $2 \lt c \lt 3$ such that $f(c) = 6$ However this contradicts the statement that $x=1$ and $x=4$ are the only solutions of the equation $f(x) = 6$ Therefore, our assumption must be false. Thus, $f(3) \gt 6$
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