Answer
$\lim\limits_{x \to 3}\frac{x^{2}-3x}{x^{2}-9}=1/2$
Work Step by Step
For the numerator $x^{2}-3x= x(x-3)$
For the denominator $x^{2}-9= (x-3)(x+3)$
Cancel (x-3)
We have $\lim\limits_{x \to 3}\frac{x}{x+3}=3/(3+3)=1/2$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 2 - Section 2.2 - The Limit of a Function - 2.2 Exercises - Page 93: 19
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