Answer
The curve
$$
r=\sqrt {1-0.8\sin^{2}\theta}
$$
is graphed in the figure and the parameter interval is $[0, 2\pi]$
Work Step by Step
The curve
$$
r=\sqrt {1-0.8\sin^{2}\theta}
$$
is graphed in the figure and the parameter interval is $[0, 2\pi]$
