Answer
$f^{-1}(3)=1$
$f(f^{-1}(2))=2$
Work Step by Step
Let $f^{-1}(3)=a, f(a)=3,$
$a^3+a^2+a=3$
try $a=1$, LHS=$1^3+1^2+1=3$=RHS
$\therefore f^{-1}(3)=1$
Let $f^{-1}(2)=b, f(b)=2,$
$\therefore f(f^{-1}(2))=f(b)=2$
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