Answer
$(a) 4$
$(b) x^{\frac{-4}{3}}$
Work Step by Step
$(a) \frac{4^{-3}}{2^{-8}}$ $=$ $\frac{2^{-6}}{2^{-8}}$ $=$ $2^{-6 + 8}$ $= 2^{2} = 4$
$(b) \frac{1}{\sqrt[3] {x^{4}}}$ = $x^{\frac{-4}{3}}$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 1 - Section 1.4 - Exponential Functions - 1.4 Exercises - Page 53: 1
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