Answer
$$0$$
Work Step by Step
$$\eqalign{
& \mathop {\lim }\limits_{\left( {x,y,z} \right) \to \left( {1,1,1} \right)} \frac{{x - \sqrt {xz} - \sqrt {xy} + \sqrt {yz} }}{{x - \sqrt {xz} + \sqrt {xy} - \sqrt {yz} }} \cr
& {\text{Evaluating}} \cr
& \mathop {\lim }\limits_{\left( {x,y,z} \right) \to \left( {1,1,1} \right)} \frac{{x - \sqrt {xz} - \sqrt {xy} + \sqrt {yz} }}{{x - \sqrt {xz} + \sqrt {xy} - \sqrt {yz} }} = \frac{{1 - \sqrt {\left( 1 \right)\left( 1 \right)} - \sqrt {\left( 1 \right)\left( 1 \right)} + \sqrt {\left( 1 \right)\left( 1 \right)} }}{{1 - \sqrt {\left( 1 \right)\left( 1 \right)} + \sqrt {\left( 1 \right)\left( 1 \right)} - \sqrt {\left( 1 \right)\left( 1 \right)} }} \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{{1 - 1 - 1 + 1}}{{1 - 1 + 1 - 1}} \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{0}{0}{\text{Ind}} \cr
& {\text{Write the function as}} \cr
& = \mathop {\lim }\limits_{\left( {x,y,z} \right) \to \left( {1,1,1} \right)} \frac{{x - \sqrt x \sqrt z - \sqrt x \sqrt y + \sqrt y \sqrt z }}{{x - \sqrt x \sqrt z + \sqrt x \sqrt y - \sqrt y \sqrt z }} \cr
& {\text{Factoring by grouping terms}} \cr
& = \mathop {\lim }\limits_{\left( {x,y,z} \right) \to \left( {1,1,1} \right)} \frac{{\sqrt x \left( {\sqrt x - \sqrt z } \right) - \sqrt y \left( {\sqrt x - \sqrt z } \right)}}{{\sqrt x \left( {\sqrt x - \sqrt z } \right) + \sqrt y \left( {\sqrt x - \sqrt z } \right)}} \cr
& = \mathop {\lim }\limits_{\left( {x,y,z} \right) \to \left( {1,1,1} \right)} \frac{{\left( {\sqrt x - \sqrt z } \right)\left( {\sqrt x - \sqrt y } \right)}}{{\left( {\sqrt x - \sqrt z } \right)\left( {\sqrt x + \sqrt y } \right)}} \cr
& {\text{Simplifying}} \cr
& = \mathop {\lim }\limits_{\left( {x,y,z} \right) \to \left( {1,1,1} \right)} \frac{{\sqrt x - \sqrt y }}{{\sqrt x + \sqrt y }} \cr
& {\text{Evaluating}} \cr
& \mathop {\lim }\limits_{\left( {x,y,z} \right) \to \left( {1,1,1} \right)} \frac{{\sqrt x - \sqrt y }}{{\sqrt x + \sqrt y }} = \frac{{\sqrt 1 - \sqrt 1 }}{{\sqrt 1 + \sqrt 1 }} \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{0}{2} \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 0 \cr} $$