Answer
(a) $12,054Pa \approx 12 kPa$
(b) $\approx 3.86 \times 10^{5} N$
(c) $\approx 3.62 \times 10^{4} N$
Work Step by Step
(a) $P = \rho gd = (820 kg/m^{3})(9.8 m/s^{2})(1.5m) = 12,054Pa \approx 12 kPa$
(b) $F = PA = (12,054Pa) (8m)(4m) \approx 3.86 \times 10^{5} N$
(c) $F = \int ^{1.5}_{0} \rho g x 4dx = (820)(9.8) 4\int^{1.5}_{0} x dx = 32,144[\frac{1}{2} x^{2}]^{3/2}_{0} \approx 3.62 \times 10^{4} N$
