Answer
$4\sqrt{5}$
Work Step by Step
$y = 2x-5$
$L = \int^{3}_{-1} \sqrt{1+(\frac{dy}{dx})^2}dx = \int^{3}_{-1}\sqrt{1+(2)^2}dx = \sqrt{5}[3-(-1)] = 4\sqrt{5} $
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