Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 8 - Techniques of Integration - 8.7 Improper Integrals - Preliminary Questions - Page 440: 2

Answer

This is an improper integral.

Work Step by Step

$\int_{0}^{\pi / 2} \cot x d x $ is an improper integral because we know that $\cot x=\dfrac{\cos x}{\sin x}$ is undefined at $ x=0$ (since $\sin 0 =0$).
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