Answer
$\cosh x$ and $sech \ x$
Work Step by Step
$\cosh x$ and $sech \ x$ are the only positive hyperbolic functions since $\cosh x= \frac{e^x+e^{-x}}{2}$ and $sech \ x= \frac{1}{\cosh x}$.
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.9 Hyperbolic Functions - Preliminary Questions - Page 384: 1
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