Chapter 7 - Exponential Functions - 7.5 Compound Interest and Present Value - Exercises - Page 355: 9

$$9.1 \%$$

Given $$ PV=7300, \ \ \ P=8000,\ \ \ t=1$$ Since \begin{align*} PV&=P e^{-rt}\\ 7300&=8000 e^{-r} \\ 7300 e^{r}&=8000 \\ e^{r}&=\frac{8000}{7300} \end{align*} Then \begin{align*} r&=\ln \frac{8000}{7300} \\ &\approx 0.0916\\ &=9.1 \% \end{align*}