Answer
$$ f(t)=9 e^{1.4 t}=9 (e^{1.4 })^t=P_0 b^t $$
where, $ P_0=9$ and $ b=e^{1.4}$.
Work Step by Step
Using the property that $ e^{xy}=(e^{x})^y $, we have
$$ f(t)=9 e^{1.4 t}=9 (e^{1.4 })^t=P_0 b^t $$
where, $ P_0=9$ and $ b=e^{1.4}$.
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