Answer
$f(x)=2x^3+x+2$
Work Step by Step
$f’’(x)=12x,$ $f’(0)=1,$ $f(0)=2$
$f’(x)=\int12xdx$
$f’(x)=6x^2+C_1$
Substitute in $f’(0)=1$ to solve for $C_1$
$1=0+C_1$
$C_1=1$
$f(x)=\int(6x^2+1)dx$
$f(x)=2x^3+x+C_2$
Substitute in $f(0)=2$ to solve for $C_2$
$2=0+0+C_2$
$C_2=2$
$f(x)=2x^3+x+2$