Answer
$ f'(1)$ is missing.
Work Step by Step
We do not have enough information. Because
$$ F'(x)=f'(g(x))g'(x)$$ and hence
$$ F'(4)=f'(g(4))g'(4)=f'(1)$$
which is missing.
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 3 - Differentiation - 3.7 The Chain Rule - Preliminary Questions - Page 145: 4
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