Answer
True.
Work Step by Step
True. Because the acceleration (the second derivative of the position) is constant (9.8 $m/sec^2$), hence the third derivative must be zero.
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 3 - Differentiation - 3.5 Higher Derivatives - Preliminary Questions - Page 135: 2
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