Answer
$h'' = fg''+2f'g'+f''g$
Work Step by Step
Let $h = fg$
$h' = fg'+gf'$
$h'' = fg''+g'f'+gf''+f'g' = fg''+2f'g'+f''g$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 3 - Differentiation - 3.5 Higher Derivatives - Exercises - Page 137: 54
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