Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - 3.4 Rates of Change - Exercises - Page 129: 13

Answer

$-1.5625$ $°C/hr$

Work Step by Step

The temperature graph around t = 4 AM (1.3, -70) (4.5, -75) $\frac{dT}{dt}$ = $\frac{-75-(-70)}{4.5-1.3}$ = $\frac{-5}{3.2}$ = $-1.5625$ $°C/hr$
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