Answer
$(\frac{f}{g})'(1) = -1$
Work Step by Step
We know that:
$(\frac{f}{g})' = \frac{gf' - fg'}{g^2}$
By substituting the values we are given, we get:
$(\frac{f}{g})'(1) = \frac{2*2 - 2*4}{2^2}$
Which can then simplify to:
$(\frac{f}{g})'(1) = -1$
