Answer
$h'$ = $\frac{f'g-fg'}{g^{2}}$
Work Step by Step
$h$ = $\frac{f}{g}$
$f$ = $hg$
$f'$ = $hg'+gh'$
$h'$ = $\frac{f'-hg'}{g}$
replace $h$ = $\frac{f}{g}$
so
$h'$ = $\frac{f'-\frac{f}{g}g'}{g}$
$h'$ = $\frac{f'g-fg'}{g^{2}}$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 3 - Differentiation - 3.3 Product and Quotient Rules - Exercises - Page 123: 62
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