Answer
$\lim_{x\to 1}f(x)=2$
Work Step by Step
We have
$ l(x) \leq f(x)\leq u(x)$
and
$\lim_{x\to 1}l(x)= \lim_{x\to 1}u(x)=2$
Then, by the squeeze theorem, we have
$$\lim_{x\to 1}f(x)=2$$
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