Answer
$g(1,3) = \frac{3}{10}$.
$g(3,-2) = \frac{-2}{13}$.
Work Step by Step
We are given the function:
$g(x,y)=\dfrac{y}{x^2+y^2}$
We plug in the points to find the function values:
$g(1,3) = \frac{3}{1^2 + 3^2}= \frac{3}{1+9} = \frac{3}{10}$.
$g(3,-2) = \frac{-2}{3^2 + (-2)^2}= \frac{-2}{9+4} = \frac{-2}{13}$.
