Answer
$$\langle -\frac{9}{2}, -\frac{3}{2}, 1\rangle.$$
Work Step by Step
$$\overrightarrow{ PQ}=Q-P=(-\frac{1}{2},\frac{9}{2},1)-(4,6,0)=\langle -\frac{9}{2}, -\frac{3}{2}, 1\rangle.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 13 - Vector Geometry - 13.2 Vectors in Three Dimensions - Exercises - Page 658: 7
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