Answer
The foci are $(0,\pm c)$.
Work Step by Step
The equation $$
\left(\frac{x}{a}\right)^{2}+\left(\frac{y}{b}\right)^{2}=1
$$
is an ellipse. Since $a\lt b$, then $c=\sqrt{b^2-a^2}$ and the foci are $(0,\pm c)$.
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