Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - 12.5 Conic Sections - Exercises - Page 635: 7

$$ \left(\frac{x}{6}\right)^{2}+\left(\frac{y}{3}\right)^{2}=1. $$

Translating the center of the ellipse $$ \left(\frac{x-8}{6}\right)^{2}+\left(\frac{y+4}{3}\right)^{2}=1 $$ to the origin, leads to the new ellipse $$ \left(\frac{x}{6}\right)^{2}+\left(\frac{y}{3}\right)^{2}=1. $$