Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - 12.4 Area and Arc Length in Polar - Exercises - Page 623: 1

Answer

$area = \frac{{25}}{4}\pi $.

Work Step by Step

We draw a circle of radius $5$. Then draw two rays that make the angles $\theta = \frac{\pi }{2}$ and $\theta=\pi$, respectively, with the $x$-axis. So, we obtain the region bounded by the circle and the rays. Using Eq. (2) of Theorem 1, the area is $area = \frac{1}{2}\cdot\mathop \smallint \limits_{\pi /2}^\pi {5^2}{\rm{d}}\theta = \frac{{25}}{2}\theta |_{\pi /2}^\pi = \frac{{25}}{4}\pi $.
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