Answer
$$180cm.$$
Work Step by Step
Since the particle has a constant speed of $3 \ cm/s$, then the distance traveled in the first minute is $$s=\int_0^{60}\sqrt{x'^2+y'^2}dt=\int_0^{60}3dt=3t|_0^{60}=180cm.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - 12.2 Arc Length and Speed - Preliminary Questions - Page 610: 5
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