Answer
The series $\sum_{k=1}^{\infty} 4^{1/k} $ diverges.
Work Step by Step
We have
$$ \lim_{k\to \infty}4^{1/k}=4^0=1.$$
Hence, the series $\sum_{k=1}^{\infty} 4^{1/k} $ diverges.
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 11 - Infinite Series - 11.3 Convergence of Series with Positive Terms - Exercises - Page 557: 59
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