Answer
$$ \Sigma_{n=0}^\infty \frac{1}{n}$$
Work Step by Step
The easiest example is the P-series:
$$ \Sigma_{n=0}^\infty \frac{1}{n}$$
it is divergent since $p=1$ (harmonic series). At the same time, we have $\lim_{n\to \infty}\frac{1}{n}=0.$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 11 - Infinite Series - 11.2 Summing and Infinite Series - Preliminary Questions - Page 547: 8
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