Answer
$$ x=\sqrt[3] 2.$$
Work Step by Step
The zeros of $f(x)=2- x^3$ can be obtained by putting
$$2-x^3=0\Longrightarrow x=\sqrt[3] 2.$$
Since $f(-x)\neq -f(x)$ nor $f(-x)\neq f(x)$ then the function is not symmetric about the origin nor about the y-axis and it is decreasing on the interval $(-\infty,\infty)$. See the figure below.
![](https://gradesaver.s3.amazonaws.com/uploads/solution/0ddbdf1f-3f53-456d-af25-6e8cb62f661c/steps_image/small_1580299284.png?X-Amz-Algorithm=AWS4-HMAC-SHA256&X-Amz-Credential=AKIAJVAXHCSURVZEX5QQ%2F20240908%2Fus-east-1%2Fs3%2Faws4_request&X-Amz-Date=20240908T000149Z&X-Amz-Expires=900&X-Amz-SignedHeaders=host&X-Amz-Signature=55c89d5b25c11105bcdcb72eadcec2b6825716c100d5a3d560703fa35c1c1dcd)