Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.3 Exercises - Page 275: 59

Answer

$a=-2$ $b=5$

Work Step by Step

Apply Theorem 4.6, Additive lnterval Property: $\displaystyle \int_{-2}^{1}f(x)dx+\int_{1}^{5}f(x)dx=\int_{-2}^{5}f(x)dx$ $a=-2$ $b=5$
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