Answer
$f'(x)=2+\frac{2}{x^3}$
Work Step by Step
$f(x)=\frac{2x^4}{x^3}-\frac{x}{x^3}=2x-\frac{1}{x^2}$
$f'(x)=(2x)'+(-x^{-2})'=2+(-2)(-1)(x^{-2-1})=2+\frac{2}{x^3}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - 2.2 Exercises - Page 114: 44
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