Chapter 3 - Review - True-False Quiz - Page 269: 9

TRUE

$\frac{d}{dx}tan^{2}x=\frac{d}{dx}(sec^{2}x)$\int Recall the property: $sec^{2}\theta=1+tan^{2}\theta$ $\frac{d}{dx}tan^{2}x=\frac{d}{dx}(1+tan^{2}x)$ $\frac{d}{dx}tan^{2}x=0+\frac{d}{dx}(tan^{2}x)$ Hence, the given statement is true.