Answer
$dy = 0.8$
Work Step by Step
$y = x^3-2x^2+1$
$\frac{dy}{dx} = 3x^2-4x$
$dy = (3x^2-4x)(dx)$
$dy = [3(2)^2-4(2)]~(0.2)$
$dy = (12-8)~(0.2)$
$dy = (4)~(0.2)$
$dy = 0.8$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 3 - Review - Exercises - Page 272: 108
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