Answer
We can see a graph of $f'(x)$ below the graph of $f(x)$
Work Step by Step
We can see a graph of $f'(x)$ below the graph of $f(x)$
$f'(x)$ is symmetric about the origin because $f'(-x) = -f'(x)$
$f'(x) \to \infty~~$ at the left endpoint and $~~f'(x) \to -\infty~~$ at the right endpoint