Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 2 - Section 2.8 - The Derivative as a Function - 2.8 Exercises - Page 161: 1

Answer

See the image below.

Work Step by Step

(a) The tangent line at $0$ is somewhat vertical with a slope of about $6$. (b) At the point $x=1$, we have a horizontal tangent line, so the derivative is $0$. (c) For this point, we have to estimate the number. If we draw a tangent line at that point, its value will be about $-\frac{3}{2}$. (d) At the point $x=3$ the slope is about $-1.3$. (e) At the point $x=4$, the tangent line becomes even less steep, but at the same time it starts to approach $0$. The tangent line is about $-0.8$. (f) At the point $x=5$, the slope continues to approach $0$ and gets a value of about $-\frac{1}{3}$. (g) At the point $x=6$, we have a horizontal tangent line, so the derivative is $0$. (From this point onward, the tangent line becomes positive). (h) At the point $x=7$, the tangent line becomes positive and its value is about $0.2$ (Note that all of these numbers are estimated. Other answers are possible.)
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