Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 2 - Section 2.6 - Limits at Infinity; Horizontal Asymptotes - 2.6 Exercises - Page 137: 9

Answer

$f(0) = 3$ $\lim\limits_{x \to 0^-}f(x) = 4$ $\lim\limits_{x \to 0+}f(x) = 2$ $\lim\limits_{x \to 4^-}f(x) = -\infty$ $\lim\limits_{x \to 4^+}f(x) = \infty$ $\lim\limits_{x \to -\infty} f(x) = -\infty$ $\lim\limits_{x \to \infty} = 3$

Work Step by Step

$f(0) = 3$ $\lim\limits_{x \to 0^-}f(x) = 4$ As $x$ approaches $0$ from the left, the value of the function gets closer and closer to 4 $\lim\limits_{x \to 0+}f(x) = 2$ As $x$ approaches $0$ from the right, the value of the function gets closer and closer to 2 $\lim\limits_{x \to 4^-}f(x) = -\infty$ As $x$ approaches $4$ from the left, the value of the function becomes larger magnitude negative numbers. $\lim\limits_{x \to 4^+}f(x) = \infty$ As $x$ approaches $4$ from the right, the value of the function becomes larger magnitude positive numbers. $\lim\limits_{x \to -\infty} f(x) = -\infty$ As $x$ approaches larger magnitude negative numbers, the value of the function becomes larger magnitude negative numbers $\lim\limits_{x \to \infty} = 3$ As $x$ approaches larger magnitude positive numbers, the value of the function gets closer and closer to 3
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