Answer
$f(0) = -2$
$f(1) = 1.7$
Work Step by Step
$e^{x} = 3 - 2x$
$e^{x} -3 + 2x = 0$
Equal this fuction to $f(x)$.
Now equal the value of $x$ to the values given in the interval: $(0,1)$.
$f(0) = e^{0} -3 + 2(0)$ $= 1 - 3 = -2$
$f(1) = e^{1} -3 + 2(1) = e^{1} - 2 = 1.7$
The intermediate value theorem takes all the values between $f(0)$ and $f(1)$. So in this case $f(x)$ will take all the values between $-2$ and $1.7$.
