Chapter 2 - Section 2.2 - The Limit of a Function - 2.2 Exercises - Page 92: 1

As $x$ approaches $2$, $f(x)$ approaches $5$. Yes, it is possible for this to be true and for $f(2)=3$.

It means that $f(x)$ becomes arbitrarily close to $3$ as we take $x$ close enough to $2$, but $x\ne2$. It is possible for $f(2)$ to equal $3$ because the limit only relies on when $f(x)$ is near $2$; there can be a hole at $x=2$.