Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 1 - Section 1.2 - Mathematical Models: A Catalog of Essential Functions. - 1.2 Exercises - Page 34: 20

Answer

a) $C=\frac{1}{4}x+260$ b) $\$635$ c) See image for graph. The slope represents the cost to drive each mile. d) The C-intercept ($\$260$) represents the cost to have the car even without driving. e) A linear function is suitable because a car's average gas mileage and cost to operate is generally consistent.

Work Step by Step

a) We have two points: $(480, 380)$ and $(800, 460)$. Find the slope. $m=\frac{C_2-C_1}{d_2-d_1}=\frac{800-480}{460-380}=\frac{1}{4}$ Now use point-slope form and solve for $C$. $C-380=\frac{1}{4}(d-480)$ $C=\frac{1}{4}d+260$ b) Plug $1500$ into $d$ $C=\frac{1}{4}(1500)+260=\$635$ c) Graph the equation found in part (a). The slope represents the rate of change of a function, which in this case is how much the cost changes per mile. d) C-intercept is 260. The y-intercept represents the y-value when x=0, which in this case is the cost when no miles are driven. e) A linear function is suitable because a car's average gas mileage and cost to operate is generally consistent.
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